![]() ![]() We divide A 1 and A 2 by -19.3258 to form the matrix: To zero A 3,4, we apply (A 3 − (−1.017)) Įigenvectors associated with the eigenvalue (λ 3 = −0.6742) are ![]() We start by dividing 39.3258 to A 1 and obtain the matrix: Interchange A 2 and A 3(A 3↔A 2) to obtain the matrix:Įigenvectors associated with the eigenvalue (λ 2 = −20) are To zero the value at A 2,1, we apply (A 2 − 20A 1) → A 2 and form the matrix: Then, apply (A 1 − 0.5A 2) → A 1, and the equivalent homogeneous system of equations isĮigenvectors associated with the eigenvalue (λ1 = 0) are Next, we perform (A 1 − (−0.5)A 3) → A 1 and have the matrix: To zero the A 2,3, we apply (A 3 − (−0.3333)A 2) → A 2 and obtain To zero A 4, we subtracting A 3 to A 4 and get the matrix:
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |